| 1 | 2 | 3 | ||||
2) | + | − | = 0 | |||
| log x | log 10x | log 100x |
| 1 | 2 | 3 | ||||
+ | − | = 0 | ||||
| log x | log 10 + log x | log 100 + log x |
| 1 | 2 | 3 | |||
+ | − | = 0 | |||
| log x | 1 + log x | 2 + log x |
| 1 | 2 | 3 | |||
+ | − | = 0 | |||
| t | 1 + t | 2 + t |
czyli dobrze kombinowalem z ta zmiana podstaw logarytmu na podstawe 10 .