Sprawdzi ktoś czy dobrze? LAPLACE Rifi: x''(t) + 2x'(t) + x(t) = 0 x(0) = 0 x'(0) = −1 s² L[x] − s*0 + 1 + 2sL[x] − 0 + L[x] = 0 s² L[x] + 1 + 2sL[x] + L[x] = 0 L[x] (s² +2s + 1) = −1

	−1
x = L−1 [		]
	s2+2s+1

x(t) = sint t e^t