D: y2<=x<=9
x=9, y2=9⇔y=3 lub y=−3
0∫9[−√x∫√x(√x−y2)dy] dx=
| x | y | y | ||||
=0∫9([ | arcsin | + | √x−y2]−√x√x)dx= | |||
| 2 | √x | √x |
| x | x | |||
=0∫9( | arcsin1− | arcsin(−1))dx= | ||
| 2 | 2 |
| πx | π | |||
=0∫9 | dx=[ | x2]09= | ||
| 2 | 4 |
| 81π | ||
= | ||
| 4 |
| 5^2 | 52 |
| 2^{10} | 210 |
| a_2 | a2 |
| a_{25} | a25 |
| p{2} | √2 |
| p{81} | √81 |
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