α=50
β=15
1) W ΔADC:
| 10 | 10 | |||
tg50o= | ⇔1.19≈ | |||
| |AD| | |AD| |
| 10 | ||
|AD|= | ⇔|AD|=8.4 | |
| 1.19 |
| 10) | ||
sin50= | ||
| |AC| |
| 10 | ||
0.77≈ | ||
| |AC| |
| 10 | 10 | |||
tg15= | ⇔0.27≈ | |||
| |BD| | |BD| |
| 10 | ||
|BD|= | ||
| 0.27 |
| 10 | ||
sin15= | ||
| |BC| |
| 10 | ||
0.26= | ||
| |BC| |
| 10 | ||
|BC|= | ||
| 0.26 |
| 5^2 | 52 |
| 2^{10} | 210 |
| a_2 | a2 |
| a_{25} | a25 |
| p{2} | √2 |
| p{81} | √81 |
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