| |x| | ||
f(x) = | zał. |x| ≠ 2 czyli x ≠ 2 i x ≠ −2 | |
| |x| − 2 |
| −x | ||
1. x ∊ (−∞; 0) ⇒ f(x) = | ale nie wiem jak doprowadzić to do wzoru funkcji | |
| −x + 2 |
| −x | (−x+2)−2 | ||
= | |||
| −x + 2 | −x+2 |
| −2 | ||
Czyli powinno wyjść ostatecznie | + 1? | |
| x + 2 |
| −x | −x | x | |||
= | = | ||||
| −x+2 | −(x−2) | x−2 |
| x | x−2+2 | x−2 | 2 | 2 | |||||
= | = | + | =1+ | ||||||
| x−2 | x−2 | x−2 | x−2 | x−2 |