1+k | ||
13+23+...+k3 + (k+1)3 = // z (2) // = (1 + 2 + ... + k)2 + (k+1)3 = ( | k)2 + | |
2 |
k2 | k2 + 4k + 4 | (k+2)2 | ||||
= (k+1)2[ | + (k+1)] = (k+1)2* | = (k+1)2 | = | |||
4 | 4 | 4 |
1 + (k+1) | ||
= ( | (k+1) )2 = (1 + 2+ ... + k + (k+1))2 | |
2 |
5^2 | 52 |
2^{10} | 210 |
a_2 | a2 |
a_{25} | a25 |
p{2} | √2 |
p{81} | √81 |
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