| arcsin(1−2x) | |
| 4x2−1 |
| acrsin(1−2x) | ||
limx−>12= | = limx−>12= | |
| (2x2−1)(2x2+1) |
| acrsin(1−2x) | 1 | |||
* | ||||
| −(−2x+1) | (2x+1) |
| acrsin(1−2x) | 1 | ||
= 1 Więc mam limx−>12 1 * | = limx−>12 | ||
| −(−2x+1) | (2x+1) |
| 1 | 1 | |||
=− | = − | |||
| (2*12+1) | 2 |
| 5^2 | 52 |
| 2^{10} | 210 |
| a_2 | a2 |
| a_{25} | a25 |
| p{2} | √2 |
| p{81} | √81 |
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