Trygonometria cdc: Oblicz: sin³x(1+ctgx)+cos³x(1+tgx)=sin2x+2sin²x Jest to zadanie z kursu PWR nawet nie wiem jak się za nie zabrać...

Mariusz: cos(x)+sin(x)=1+sin(2x)−cos(2x) cos(x)+sin(x)=(cos(x)+sin(x))²−(cos(x)+sin(x))(cos(x)−sin(x)) (cos(x)+sin(x))−(cos(x)+sin(x))²+(cos(x)+sin(x))(cos(x)−sin(x))=0 (cos(x)+sin(x))(1−(cos(x)+sin(x))+(cos(x)−sin(x)))=0 (cos(x)+sin(x))(1−cos(x)−sin(x)+cos(x)−sin(x))=0 (cos(x)+sin(x))(1−2sin(x))=0

	1		1
√2(		cos(x)+		sin(x))(1−2sin(x))=0
	√2		√2

	π
√2sin(x+		)(1−2sin(x))=0
	4

	π
sin(x+		)(1−2sin(x))=0
	4

	π		1
sin(x+		)=0 ⋁ sin(x)=
	4		2