logarytm
Wish you were here: Dany jest log303=a i log305 =b
Znalezc log308
16 lut 19:54
ZKS:
log308 = 3(1 − a − b)
16 lut 20:09
iteRacj@:
log
305=b
| | 30 | |
b=log305=log30( |
| )=1−log306=1−log30(2*3)=1−(log302+log303)= |
| | 6 | |
=1−log
302−a → log
302=1−a−b
log
308=log
30(2
3)=3log
302
16 lut 20:13
Wish you were here: Dzieki za rozpisanie
16 lut 20:25