| 3 | 3 | |||
sin | π*cos | π | ||
| 8 | 8 |
| 1 | ||
ze wzoru sinx cos x= | sin 2x | |
| 2 |
| 1 | 3 | |||
dostajesz | sin | π | ||
| 2 | 4 |
| 1 | ||
sin2x = 2sinxcosx ⇔ sinxcosx = | sin2x | |
| 2 |
| 1 | 3 | 1 | 3 | |||||
sin3/8xcos3/8x = | sin(2* | x) = | sin( | x) | ||||
| 2 | 8 | 2 | 4 |
Dosłownie przed chwila jeszcze znalazłam wzór
| 1 | ||
sinαcosβ= | [sin(α−β)+sin(α+β)] | |
| 2 |
