p | ||
skoro obwód to 2p ... to bok = | ||
2 |
p2 | ||
x2 + y2 = | ||
4 |
fe | ||
f+e=m i 4a=2p ⇒2a=p i P= | ||
2 |
fe | ||
f2+e2=4a2 ⇒(f+e)2−2fe=p2⇒ m2−4* | =p2 | |
2 |
fe | m2−p2 | ||
=P= | , m>p>0 | ||
2 | 4 |
5^2 | 52 |
2^{10} | 210 |
a_2 | a2 |
a_{25} | a25 |
p{2} | √2 |
p{81} | √81 |
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