1i2 pochodna
Passtor: jaka wyjdzie pochodna 1 i 2 w przykładzie (2−lnx)lnx
14 lut 13:43
Edek: f(x)=(2−lnx)lnx
| | −1 | | 1 | | −lnx | | 2 | | lnx | | 2−2lnx | |
f'(x)= |
| lnx+(2−lnx)* |
| = |
| + |
| − |
| = |
| |
| | x | | x | | x | | x | | x | | x | |
| | | | −2−2+2lnx | | 2lnx−4 | |
f''(x)= |
| = |
| = |
| |
| | x2 | | x2 | | x2 | |
Oczywiście D
f(x)=D
f'(x)=D
f''(x)=x>0
14 lut 15:01
Passtor: dziekuje bardzo
14 lut 16:51