czy ma być tak?
√x −√x+2 czy tak? ... √(x −1)√x+2
1) x+2 ≥0 => x ≥−2
i 2) x−1 −√x+2≥0 => x −1 ≥√x+2 |2
x2 −2x +1 ≥ x+2 => x2 −3x −1≥0 Δ= 13 √Δ= √13
| 3+√13 | 3−√13 | |||
x1= | v x2 = | |||
| 2 | 2 |
| 3−√13 | 3+√13 | |||
x€ (−∞, | > U < | ,∞)
| ||
| 2 | 2 |