xxx Ejuch: \lim_{x \to +\infty} f(x) =\lim_{x \to +\infty} \frac{\sqrt{x²+9}}{−x+3} = \lim_{x \to +\infty} \frac{x\sqrt{1+\frac{9}{x²}}}{x(−1+\frac{3}{x})} = [\frac{1}{−1}] = −1

moze pomoge: dobrze

Blee:

	√x2+9
lim
	3−x

tak ... dobrze

jc: x→∞ ? granica = −1

Qwerty: juz nic