| 1+22005 | 1+22006 | |||
C) a= | b= | |||
| 1+22006 | 1+22007 |
b)
(42)50 = 1650
(33)50 = 950
więc
c)
| 1 + 22005 | 1 + 22005 | ||
= | = | ||
| 1 + 22006 | 1 + 2*22005 |
| 1 | 2 + 2*22005 | 1 | 1 + 2*22005 + 1 | |||||
= | * | = | * | = | ||||
| 2 | 1 + 2*22005 | 2 | 1 + 2*22005 |
| 1 | 1 | 1 | ||||
= | + | * | ||||
| 2 | 2 | 1+ 22006 |
| 1 + 22006 | 1 | 1 | 1 | ||||
= | + | * | |||||
| 1 + 22007 | 2 | 2 | 1+ 22007 |