| n3 + n2 +n −3 | ||
Oblicz granicę ciągu an=( | )6n−3 | |
| n3 − 4n2 + 5n − 6 |
| 5n2−4n+3 | ||
an = (1+ | )6n−3 | |
| n3−4n2+5n−6 |
| n3−4n2+5n−6 | 5n2−4n+3 | |||
6n−3 = | ( | (6n−3) ) | ||
| 5n2−4n+3 | n3−4n2+5n−6 |
| n3−4n2+5n−6 | ||
gdzie xn = | → ∞ | |
| 5n2−4n+3 |
| 5n2−4n+3 | ||
yn = | (6n−3) → 30 | |
| n3−4n2+5n−6 |
| 5^2 | 52 |
| 2^{10} | 210 |
| a_2 | a2 |
| a_{25} | a25 |
| p{2} | √2 |
| p{81} | √81 |
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