x2−2x−7 | A | B | Cx+D | ||||
= | + | + | |||||
(x−1)2(x2+2x+5) | x−1 | (x−1)2 | x2+2x+5 |
A | B | |||
całkę z | i | łatwo wyliczysz | ||
x−1 | (x−1)2 |
Cx+D | ||
dla | , Cx+D = a(x2+2x+5)' + b | |
x2+2x+5 |
x2−2 x−7 | 1−x | 1 | 1 | ||||
= | + | − | |||||
(x2−2 x+1)(x2+2 x+5) | 2(x2+2 x+5) | 2 (x−1) | (x−1)2 |
5^2 | 52 |
2^{10} | 210 |
a_2 | a2 |
a_{25} | a25 |
p{2} | √2 |
p{81} | √81 |
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