wyrażenia algebraiczne
Monia: Jeśli 1+14+19+116+...=s, to suma 14+116+136+... jest równa
2 lip 10:28
ford:
| | 1 | |
1+14+19+116+... = ∑ |
| = s |
| | n2 | |
| | 1 | | 1 | | 1 | | 1 | | 1 | |
14+116+136 = ∑ |
| = ∑ |
| = |
| ∑ |
| = |
| s |
| | (2n)2 | | 4n2 | | 4 | | n2 | | 4 | |
2 lip 10:33
Monia: dziękuję
2 lip 10:37
Lech: S1 = ∑ (1/n2 )
S2 = ∑ (1/(2n)2 )
S3 = ∑ (1/(2n +1)2)
S2 = S1 − S3= ..........
2 lip 10:37