| 3√a | ||
Wiedząc, że logab a = 4 oblicz logab | ||
| √b |
| 3√a | ||
logab | = logab3√a − logab√b = 13logaba − 12logabb= | |
| √b |
| 1 | 1 | |||
= 43 −12 | = 43 −12 | = | ||
| logbab | logba +logbb |
| 1 | ||
=43 −12 | ||
| logba +1 |
| 1 | ||
logaba = | =4 więc logba=−4/3 | |
| logab +1 |
| 1 | ||
=43 −12 | =4/3+3/2 | |
| −4/3 +1 |
| 1 | ||
to logx y= | ||
| logy x |
| 1 | 3 | 4 | 3 | |||||
logab (a1/3*a−3/8) = logaba(1/3)+(3/8) = ( | + | )*4= | + | |||||
| 3 | 8 | 3 | 2 |
| 1 | 1 | 1 | ||||
logaba= | = | = | ||||
| logaab | logaa+logab | 1+logab |
| 1 | |
=4 | |
| 1+logab |
| 1 | ||
logab= | =−3/4 | |
| logba |
| 1 | ||
logba= | = −4/3 | |
| −3/4 |
| 5^2 | 52 |
| 2^{10} | 210 |
| a_2 | a2 |
| a_{25} | a25 |
| p{2} | √2 |
| p{81} | √81 |
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