Jak podstawić logarytmy?
wffix: Wiedząc, że log2=a i log3=b, oblicz log144
19 lut 18:22
Jerzy:
| | log12144 | |
Wskazówka: log144 = |
| |
| | log1210 | |
| | 1 | | 1 | |
log1210 = |
| = |
| |
| | log12 | | log3 + 2log2 | |
19 lut 18:26
Satan: Prościej: log144 = log122 = 2log12 = 2(log4 + log3) = 2(2log2 + log3) = 2(2a + b) = 4a + 2b
19 lut 18:37