| logx(x) | 1 | |||
logx(y)= | −> logx(y)= | |||
| logx(y) | logx(y) |
| 1 | ||
narysować, ale co z tą drugą?( | ) | |
| logx(y) |
logxy=logyx
x, y>0 oraz x, y≠1
| lny | lnx | ||
= | |||
| lnx | lny |
D:
x>0 i y>0 i x≠1 i y≠1
| logx(x) | ||
logx(y)= | ⇔ | |
| logx(y) |
| 1 | ||
logx(y)= | ⇔ | |
| logx(y) |
| 1 | ||
y=x lub y= | tylko I ćwiartka | |
| x |