calka
werty: Potrzebuje pomocy z calka:
10 sty 20:36
karty do gry :
t = 3√x − 2 + 1
x = (t−1)3 + 2
dx = 3(t−1)2 dt
10 sty 20:37
Lech:
Podstawienie : x−2 =t
3 ⇒ dx = 3t
2 dt
| | 3t2 dt | | t2 − 1 | | dt | |
Calka ∫ |
| = 3 [ ∫ |
| dt + ∫ |
| ] = |
| | t+1 | | t+1 | | t+1 | |
| | dt | |
= 3 [ ∫ (t−1) dt + ∫ |
| dt ] = ..... |
| | t+1 | |
10 sty 20:41
werty: | | 3t2 − 6t + 3 | | 3 | |
= ∫ |
| dt = ∫3tdt − ∫6dt + ∫ |
| |
| | t | | t | |
itd.
dobrze?
10 sty 22:22