| 5 | ||
wychodzi mi cos takiego i nwm czy dobrze logx 6= log2 6 | ||
| 4 |
| 1 | ||
log86= | log26 | |
| 3 |
| log26 | log26 | (log26)2 | ||||
(1+log23)*(log86)=(log22+log23)( | )=(log26)* | = | ||||
| log28 | 3 | 3 |
| (log26)2 | ||
(logx36)2= | ||
| 3 |
| ±log26 | ||
logx36= | ||
| √3 |
| log636 | ±log26 | ||
= | |||
| log6x | √3 |
| ±2√3 | ±(log24)√3 | |||
log6x= | = | =±√3(log64)=log6(4±√3) | ||
| log26 | log26 |