6 | ||
a)log6−log2−log3=log( | )−log3=... | |
2 |
8 | ||
b) 3log2−log80+log1=log23−log(80*1)=log8−log80=log( | )=... | |
80 |
a | ||
loga−logb−logc = log | ||
b*c |
6 | ||
a) log | =log1=0 | |
2*3 |
8*1 | ||
b) log | = log0,1= −1 | |
80 |
5^2 | 52 |
2^{10} | 210 |
a_2 | a2 |
a_{25} | a25 |
p{2} | √2 |
p{81} | √81 |
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