log boniek: Witam mam problem z przykładem poratuje ktoś? X⁽3−log(x/3))= 900  

boniek: poprawka x⁽3−log(x/3))=900

boniek: Chodzi o to że 3− log(x/3) jest w potędze

iteRacj@: x>0 x^w = 900 w= 3−log(^x₃) logarytmuję stronami logx^{3−log(x₃)} = log(900) [3−log(^x₃)]*log(x) = log(900) [2+1−log(^x₃)]*log(x) = log(30²) [2+log(10)−(log(x)−log(3))]*log(x) =2*log(30) [2+log(10)+log(3)−log(x)]*log(x) =2* log(30) [2+log(30)−log(x)]*log(x) − 2*log(30) =0 −log(x)*log(x)+log(30)*log(x) − 2*log(30)+2*log(x)=0 −log(x)[log(x)−log(30)]+2[log(x)−log(30)]=0 [−log(x)+2]*[log(x)−log(30)]=0 −log(x)+2=0 lub log(x)−log(30)=0 i dalej juz rozwiążesz