16 | ||
1/2log29+2log2(4/3)=log291/2+log2(4/3)2=log23+log2(16/9)=log2(3* | )= | |
9 |
16 | ||
=log2 | ||
3 |
16 | ||
Teraz: log2x=log2 | ⇒ x=16/3 | |
3 |
16 | ||
log2x=log23+log2 | ||
9 |
16 | ||
log2x=log2(3* | ) | |
9 |
16 | ||
log2x=log2 | ||
3 |
16 | ||
x= | ||
3 |
5^2 | 52 |
2^{10} | 210 |
a_2 | a2 |
a_{25} | a25 |
p{2} | √2 |
p{81} | √81 |
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