logarytm zbn137: Obliczyć 2x^{log_2/3 x} = ⁴√32/3

Eta: x>0 , log_2/3x=a ⇒ x=(2/3)^{a 4}√32/3= 2⁴√2/3 =2* (2/3)^1/4 [(2/3)^a]^a= (2/3)^1/4⇒ a²=1/4 ⇒ a=1/2 v a= −1/2 to log_2/3x=1/2 v log_2/3x= −1/2 x= √2/√3 =√6/3 v x= √6/2 =====================