1 | 1 | log25 | log25 | |||||
log365 = log62 5 = | log65 = | * | = | |||||
2 | 2 | log26 | 2a |
1 | 1 | 1 | ||||
a = log62 = | = | = | ||||
log26 | log22 + log23 | 1+log23 |
1 | 1 | |||
a = | ... stąd: log23 = | − 1 | ||
1+log23 | a |
1 | ||
b = log65 = 2* | log65 = 2*log365 | |
2 |
b | ||
czyli: log365 = | ||
2 |
5^2 | 52 |
2^{10} | 210 |
a_2 | a2 |
a_{25} | a25 |
p{2} | √2 |
p{81} | √81 |
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