x+1 | ||
f(x) = ( | )5 | |
x |
x+1 | x+1 | x+1 | ||||
f'(x) =[ ( | )5]' = 5 * ( | )4 * ( | )' = | |||
x | x | x |
(x+1)4 | 1*x−(x+1) | |||
= 5 * | * | = | ||
x4 | x2 |
(x+1)4 | −1 | (x+1)4 | ||||
= 5 * | * | = −5 * | ||||
x4 | x2 | x6 |
1 | ||
A jak bedzie f(x)= x+ | ? | |
x |
5^2 | 52 |
2^{10} | 210 |
a_2 | a2 |
a_{25} | a25 |
p{2} | √2 |
p{81} | √81 |
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