log i tryg zul:

	3
niech x∊[0,π/2] oraz log24sinx(24cosx)=		.
	2

Oblicz 24ctg²x.

kochanus_niepospolitus:

	3
logab =		−> 2logab = 3 −> logab2 = 3 −> a3 = b2
	2

(24sinx)³ = (24cosx)² // : 24² 24sin³x = 1 − sin²x t = sinx ; t∊<−1;1> 24t³ + t² − 1 = 0 (3t−1)(8t²+3t+1) = 0

	1		√8
sinx =		−> cosx =
	3		3

24ctg²x = 24*8 = 192