Wieoomiany
...:: | | 1 | |
− |
| (x−1)(x+3)(x+5) = x2+2x−3 |
| | 2 | |
25 sty 17:54
Julek: x2 + 2x − 3
Δ = 4+12 = 42
x1=−2+42 = 1
x2=−2−42 = −3
−12 (x−1)(x+3)(x+5) = (x−1)(x+3)
x∊{−3;1}
25 sty 18:10
ak1: −12(x−1)(x+3)(x+5)=(x−1)(x+3) |:(x−1)(x+3)
−12(x+5)=1 |*−2
x+5=−2
x=−7
25 sty 18:25