algebra
Klulak: oblicz wartosc x2+y2+z2 jezeli x+y−z=13 i 1/x+1/y−1/z=0
1 maj 20:58
Matura 2017:
x,y,z≠0
| 1 | | 1 | | 1 | | yz+xz−xy | |
| + |
| − |
| =0 ⇔ |
| =0 ⇒ xz+yz= xy⇒ −2xz−2yz= −2xy |
| x | | y | | z | | xyz | |
(x+y−z)
2=169
x
2+y
2+z
2+2xy−2xz−2yz=169
x
2+y
2+z
2 +2xy−2xy=169
x
2+y
2+z
2=169
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1 maj 21:10