| n+2 | ||
Granica ciągu ( | )2n dla n→∞ jest: | |
| n+3 |
| 1 | ||
b) większa od | ||
| 9 |
| n+2 | 1 | −1 | |||
= 1− | = 1+ | ||||
| n+3 | n+3 | n+3 |
| 1 | ||
A garnica takiego ciagu limn→∞(1+ | )n mowi Ci cos ? | |
| n |
| −1 | ||
= lim n→∞[(1+ | )n+3]2n/n+3=e−2 | |
| n+3 |
| 1 | ||
e−2}= | ≈0,135335 | |
| e2 |
| n +2 |
| ||||||||||||
an = ( | )2n = [( | )n]2 | |||||||||||
| n + 3 |
|
| e2 | 1 | 1 | ||||
lim an = [ | ]2 = [ e−1]2 = e−2 = | > | ||||
| e3 | e2 | 9 |
| 5^2 | 52 |
| 2^{10} | 210 |
| a_2 | a2 |
| a_{25} | a25 |
| p{2} | √2 |
| p{81} | √81 |
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