jeśli kąt
kamil852: Jeśli kąt ostry ma miarę α i 2sinα=3cosα to oblicz sinα i cosα
4 kwi 21:00
Janek191:
2 sin α = 3 cos α
r
2 = (2 x)
2 + (3 x)
2 = 13 x
2
r =
√13 x
więc
| 3 x | | 3 | | 3 √13 | |
sin α = |
| = |
| = |
| |
| √13 x | | √13 | | 13 | |
| 2 x | | 2 | | 2 √13 | |
cos α = |
| = |
| = |
| |
| √13 x | | √13 | | 13 | |
4 kwi 21:06