| √1+x−4√1+x | ||
lim | ||
| x |
| 0 | ||
Mi po przekształceniach wychodził symbol nieoznaczony | ||
| 0 |
| a+b | ||
a−b = (a−b)* | ||
| a+b |
| √1+x−4√1+x | 4√1+x−1 | |||
limx→0 | =limx→04√1+x* | = | ||
| x | x |
| √1+x−1 | ||
=limx→04√1+x* | = | |
| x(4√1+x+1) |
| x | 1 | |||
=limx→04√1+x* | =limx→04√1+x* | = | ||
| x(4√1+x+1)(√1+x+1) | (4√1+x+1)(√1+x+1) |
| 1 | ||
= | ||
| 4 |