| √x + 2 − 2 | ||
Oblicz granicę lim x→2 | ||
| 7x − 14 |
| 0 | |
=1 | |
| 0 |
| √x+2−2 | (x+2)−4 | |||
limx→2 | =limx→2 | = | ||
| 7x−14 | 7(x−2)(√x+2+2) |
| 1 | 1 | |||
=limx→2 | = | |||
| 7√x+2+14 | 28 |
| 0 | 0 | |||
[ | ] to symbol nieoznaczony... | ≠1. | ||
| 0 | 0 |
| √x+2−2 | 0 | (√x+2−2)' | ||||
limx→2 | = [ | ] = limx→2 | = | |||
| 7x−14 | 0 | (7x−14)' |
| 1 | |||||||||
=limx→2 | = | |||||||||
| 7 | 28 |
| 5^2 | 52 |
| 2^{10} | 210 |
| a_2 | a2 |
| a_{25} | a25 |
| p{2} | √2 |
| p{81} | √81 |
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