| 1 | ||
sin(x)cos(x) − 1 = | sin(2x) − 1 | |
| 2 |
| 1 | 1 | 1 | ||||
− | ≤ | sin(2x) ≤ | ||||
| 2 | 2 | 2 |
| 3 | 1 | 1 | ||||
− | ≤ | sin(2x) − 1 ≤ − | ||||
| 2 | 2 | 2 |
| 1 | 1 | |||
sinxcosx = | * 2sinxcosx = | sin2x | ||
| 2 | 2 |
| 1 | 1 | 1 | ||||
− | ≤ | *sin2x ≤ | ||||
| 2 | 2 | 2 |
| 3 | 1 | 1 | ||||
− | ≤ | sin2x − 1 ≤ − | ||||
| 2 | 2 | 2 |
| 1 | ||
to f(x)= | sin(2x)−1 | |
| 2 |
| 1 | 1 | 1 | ||||
− | ≤ | sin(2x)≤ | \ −1 | |||
| 2 | 2 | 2 |
| 1 | 1 | |||
−1,5≤ | sin(2x)−1≤ − | |||
| 2 | 2 |
ale "sypnęło" jak .................
| 3 | ||
Mam nadzieję ,że wiesz iż .... − | = −1,5 | |
| 2 |
| 5^2 | 52 |
| 2^{10} | 210 |
| a_2 | a2 |
| a_{25} | a25 |
| p{2} | √2 |
| p{81} | √81 |
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| Twój nick | |