sin(x+π5) = √32
| π | π | π | π | |||||
x+ | = | +2kπ lub x+ | =π− | +2kπ . k∊C | ||||
| 5 | 3 | 5 | 3 |
| π | π | π | π | |||||
x + | = | + 2kπ lub x + | = (π − | ) + 2kπ | ||||
| 3 | 6 | 3 | 3 |
| π | √3 | |||
sin( | )= | |||
| 3 | 2 |
| π | π | |||
sin(x+ | )= sin | |||
| 5 | 3 |
| √3 | π | π | ||||
sinx = | ⇔ x = | + 2kπ lub x = π − | + 2kπ | |||
| 2 | 3 | 3 |
| 5^2 | 52 |
| 2^{10} | 210 |
| a_2 | a2 |
| a_{25} | a25 |
| p{2} | √2 |
| p{81} | √81 |
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