zad
Ania: 4x+1 = 8 + 2x+1
co dalej
23 sty 21:56
piotr: 4*2
2x−2*2
x−8=0
2*2
2x−2
x−4=0
Δ=1+32=33
23 sty 22:03
Mila:
4
x*4=8+2
x*2
4*2
2x−2*2
x−8=0
2
x=t,t>0
4t
2−2t−8=0 /:2
2t
2−t−4=0
Δ=1+4*2*4=33
| | 1−√33 | | 1+√33 | |
t= |
| <0 ∉D lub t= |
| |
| | 4 | | 4 | |
x=log
2(1+
√33)−log
24
x=log
2(1+
√33)−2
23 sty 22:06