1 | ||
3 / P(ABC) = | *h*|AC| , h= 2 , |AC|= m−1 i m>4 | |
2 |
6m−8 | 3m−8 | |||
xE= | , yE= | |||
m | m |
6m−8 | 2m−8 | 2(m−4) | ||||
h1 trójkąta DEC : y=xE −3−1= | −4 = | = | ||||
m | m | m |
1 | ||
P(DEC)= | *|DC|*h1 , |DC|= m−4 i m>4 , | |
2 |
m−4)2 | ||
P(DEC)= | ||
m |
2(m−4)2 | ||
m−1= | i m>4 ⇒ m = ....................... | |
m |
5^2 | 52 |
2^{10} | 210 |
a_2 | a2 |
a_{25} | a25 |
p{2} | √2 |
p{81} | √81 |
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