| 1 | 3 | |||
∫(x2+x+1)2dx=∫((x+ | )2+ | )2dx | ||
| 2 | 4 |
| 1 | √3 | |||
x+ | = | t | ||
| 2 | 2 |
| √3 | ||
dx= | dt | |
| 2 |
| √3 | 3 | 3 | |||
∫( | t2+ | )2dt | |||
| 2 | 4 | 4 |
| 9 | |
√3∫(t2+1)2dt | |
| 32 |
| t3 | 2 | |||
∫(t2+1)2dt=t(t2+1)2−4( | (t2+1)− | ∫t4dt) | ||
| 3 | 3 |
| 4 | 8 | |||
∫(t2+1)2dt=t(t2+1)2− | t3(t2+1)+ | t5+C | ||
| 3 | 15 |
| 5^2 | 52 |
| 2^{10} | 210 |
| a_2 | a2 |
| a_{25} | a25 |
| p{2} | √2 |
| p{81} | √81 |
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