S | ||
zatem | − a = h | |
2a |
S | 1 | |||
V(a) = a2 * ( | − a) = | aS − a3 | ||
2a | 2 |
1 | ||
V'(a) = | S − 3a2 | |
2 |
1 | |
S = 3a2 | |
2 |
1 | ||
a2 = | S | |
6 |
√6 | ||
a = | √S | |
6 |
√6 | ||
V(a) osiaga maksimum dla a = | √S | |
6 |
1 | √6 | √6 | ||||
i wynosi V(a) = | * | √S − ( | √S)3 = ... | |||
2 | 6 | 6 |
5^2 | 52 |
2^{10} | 210 |
a_2 | a2 |
a_{25} | a25 |
p{2} | √2 |
p{81} | √81 |
Kliknij po więcej przykładów | |
---|---|
Twój nick | |