Oblicz:
magellan: Wiedząc, że:
log54=a oraz log527=b oblicz: log56
15 gru 20:31
Jack:
| | 1 | | 1 | |
log54 = log522 = 2log52, zatem log52 = |
| log54 = |
| a |
| | 2 | | 2 | |
| | 1 | | 1 | |
log527 = log533 = 3log53, zatem log53 = |
| log527 = |
| b |
| | 3 | | 3 | |
log
56 = log
5(2*3) = log
52 + log
53 = ...
15 gru 20:35