oblicz pochodną
dzakiczan: x do potegi x2
9 gru 17:08
Jack:
a
logab = b
zatem
e
ln b = b
czyli x
x2 = e
ln xx2 = e
x2 ln x
(x
x2})' = (e
x2 ln x)' = e
x2 ln x * (x
2 ln x)' =
| | 1 | |
= xx2 * (2x lnx + |
| *x2) = xx2 * (2x lnx + x) |
| | x | |
9 gru 17:15
dzakiczan: dziekie wielkie
9 gru 17:17