Analiza matematyczna
Adi1:
lim sin (2x2)
−−−−−−−−−−−−
x−>0 x3+x2
2 gru 19:29
Adamm: | | sin(2x2) | | 2x2 | |
=limx→0 |
| * |
| = |
| | 2x2 | | x3+x2 | |
| | sin(2x2) | | 2 | |
= limx→0 |
| * |
| = 2 |
| | 2x2 | | x+1 | |
2 gru 19:36
Janek191:
| | sin (2 x2) | | sin (2 x2) | | 1 | |
f(x) = |
| = 2* |
| * |
| |
| | x2*( x + 1) | | 2 x2 | | x + 1 | |
więc
lim f(x) = 2*1*1} = 2
x→0
2 gru 19:38