Matma LIBRE: Zapisz w jak najprostszej postaci : a) (x+4)+(2x−6)= b) −(2y+3x)+(−4y+2x+1)= c)−(x−2xy)−(4x+xy)+(xy−x)= d) (x2+2x+1)−(x2−4x+3)=

rozalia: a) (x+4)+(2x−6)=x+4+2x−6= 3x−2 b) −(2y+3x)+(−4y+2x+1)= −2y−3x−4y+2x+1=−x−6y+1 c) −(x−2xy)−(4x+xy)+(xy−x)=−x+2xy−4x−xy+xy−x= −4x+2xy d) (x²+2x+1)−(x²−4x+3)=x² +2x+2−x²+4x−3= 6x−1