| √2 | ||
nierównosc |sin(2x−π)| < | wiec | |
| 2 |
| √2 | √2 | |||
sin(2x−π) < | lub sin(2x−π) < − | ![]() | ||
| 2 | 2 |
| 5π | 7π | 3π | π | |||||
x < | + kπ lub x< | + kπ lub x< | + kπ lub x< | + kπ | ||||
| 8 | 8 | 8 | 8 |
| 3π | 5π | |||
gdzie robie błąd? i jak odczytac z tego zbior x? w w odp x∊( | +kπ; | +kπ) U | ||
| 8 | 8 |
| 7π | 9π | |||
( | + kπ; | + kπ) | ||
| 8 | 8 |
| √2 | ||
lub sin(2x − π) > − | ||
| 2 |
| √3 | √3 | √3 | ||||
|a| < | ⇔ − | < a < | ||||
| 2 | 2 | 2 |