| 1 | ||
Wiedząc, że α jest kątem rozwartym i sinα = | , oblicz wartość wyrażenia 2sinα − | |
| 3 |
| 1 | ||
cosα + 4tgα. | ||
| 2 |
| √2 | ||
tgα=− | ||
| 4 |
| 2 | 2√2 | ||
− | |||
| 3 | 3 |
| 2−2√2 | |
może tak być  | |
| 3 |
| 1 | 8 | |||
cos2α=1− | = | |||
| 9 | 9 |
| 2√2 | ||
cosα= | ||
| 3 |
| sinα | 1 | 3 | √2 | |||||
tgα= | = | * | = | |||||
| cosα | 3 | 2√2 | 4 |
| 1 | 1 | 1 | 2√2 | √2 | 2 | √2 | ||||||||
2sinα− | cosα+4tgα=2* | − | * | +4* | = | − | +√2= | |||||||
| 2 | 3 | 2 | 3 | 4 | 3 | 3 |
| 2 | √2 | 3√2 | 2−√2+3√2 | 2+2√2 | 2(1+√2) | ||||||
− | + | = | = | = | |||||||
| 3 | 3 | 3 | 3 | 3 | 3 |
| 5^2 | 52 |
| 2^{10} | 210 |
| a_2 | a2 |
| a_{25} | a25 |
| p{2} | √2 |
| p{81} | √81 |
| Kliknij po więcej przykładów | |
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| Twój nick | |