Rafał: log_1/2x-log_1/2(x+2)>2

Mycha: log_1/2(x/(x+2))>log_1/21/4 zał: x>0 wnioskujac x+2>0 x>-2 x/(x+2)<1/4 x(x+2)<1/4(x²+2x+4) x²+2x<1/4x²+1/2x+1 3/4x²+3/2x-1<0 3x²+6x-4<0 Δ=36+48 Δ=84 √Δ=2√21 x₁= -1-1/3√21 x₂= -1+1/3√21 x∈(-1-1/3√21; -1+1/3√21) x>0 x∈(0;-1+1/3√21)