Mila:
(3 + i ) z
2 + (1 − i)z −6i =0 /*(3−i)
(9+1)z
2+(1−i)*(3−i)z−6i*(3−i)=0
10z
2+(−4i+2)z+(−18i+6i
2)=0
10z
2−(4i−2)z−6−18i=0 /:2
5z
2−(2i−1)z−3−9i=0
Δ=(2i−1)
2−4*5*(−3−9i)=57+176i
57+176i=(x+iy)
2
x
2−y
2=57
2xy=176
xy=88
stąd x
2=−64 nie odp. zał. lub x
2=121
x=11 lub x=−11
(57+176i)=(11+8i)
2 lub (57+176i)=(−11−8i)
2
| 2i−1−11−8i | | −12−6i | | 2i−1+11+8i | | 10+10i | |
z1= |
| = |
| lub z1= |
| = |
| |
| 10 | | 10 | | 10 | | 10 | |